90.0k views
3 votes
Find a polynomial f(x) of degree 3 with real coefficients and the following zeros. -2,- 2+i. ​

1 Answer

2 votes

Answer:

f(x) = x^3 + 2x^2 + x + 2

Explanation:

If -2 + i is a zero, then -2 - i must also be a zero.

These zeros are -2, -2 + i and -2 - i, and the corresponding factors of the polynomail f(x) are (x + 2), (x + 2 - i) and (x + 2 + i).

(x + 2 - i) and (x + 2 + i) multiplied together becomes x^2 + 1.

Multiplying this result by the 3rd and last factor, (x + 2), we get

(x^2 + 1)(x + 2) = x^3 + 2x^2 + x + 2

Check, using synthetic division. What are the factors of x^3 + 2x^2 + x + 2?

-2 / 1 2 1 2

-2 -2 -2

-----------------------

1 0 -1 0 Since the remainder is zero, we know that

(x + 2) is a factor and -2 is a root.

User Reallynice
by
4.0k points