Question

The length of a rectangle is 4m longer than its width.

If the perimeter of the rectangle is 56m, find its length and width.

Answer 1

Call the length a, the width b

Perimeter = (a+b) x 2

We have : a - b = 4 and (a+b) x 2 = 56

-> a + b = 28
-> a - b = 4

=> a+b + (a-b) = 32
2a = 32
a = 16
b = 56:2-16 = 12

So, the length = 16 and the width = 12