Question

1. if m<b = 60 what is AB

2. if m<b =45 what is the perimeter of the trapezoid.​

Answer 1

Answer:....

Explanation:

first we need to find the base of the triangle, so the total is 20, they also give us 12, so we subtract 20-12=8 now divide. 8/2=4. Now we use the 4 and the 60. We use SOH-CAH-TOA, they give us the base now we need to find AB which is the hypotenuse. So we take out the TOA, and the 4 is the adjacent so we take out the SOH, we have CAH now, so we use cos. Now equation time....

`cos60=(4)/(x)` since x is the bottom we switch
`(4)/(cos60)`, which equals 8. AB=8.

Now to find the perimeter. We still use the 4 to find the hypotenuse so we can find the outside side. For this one they tell us to use 45, so now lets see what method we use. SOH-CAH-TOA. We need the hypotenuse and they give us the adjacent, so we use cos again. Now setting up the equation...

`cos45=(4)/(x)` x is at the bottom again to we switch.

`(4)/(cos45)` which equals to 5.657 or you can round it. Now we add everything.

20+12+5.657+5.657= 45.314 or you can round it to 45.