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You are putting together treat bags for a birthday party. You want to put the same number of each kind of item into each bag, and have no leftover items. You have the following items for your bags:

108 pieces of gum
192 stickers
168 pieces of candy
What is the maximum number of bags you can make?
How many pieces of gum will be in each bag?
How many stickers will be in each bag?
How many pieces of candy will be in each bag?

User Yogesh D
by
5.1k points

1 Answer

7 votes

Answer:

The maximum number of bags you can make = 12

9 pieces of gum in each bag

16 stickers in each bag

14 pieces of candy in each bag

Explanation:

Pieces of gum = 108

Stickers = 192

Pieces of candy = 168

Find the highest common factor of 108, 192, 168

108 = 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, and 108

192 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, and 192

168 = 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, and 168

The highest common factor of 108, 192 and 168 is 12

The maximum number of bags you can make = 12

How many pieces of gum will be in each bag?

= 108/12

= 9 pieces of gum in each bag

How many stickers will be in each bag?

= 192/12

= 16 stickers in each bag

How many pieces of candy will be in each bag?

= 168/12

= 14 pieces of candy in each bag

User Danielmhanover
by
5.1k points