Answer:
P(4, H) = 1/12
Explanation:
Here we have two events, let's count the number of outcomes in each one of them.
Rolling a die.
Here we have 6 possible outcomes (1, 2, 3, 4, 5, 6)
Flipping a penny.
Here we have two possible outcomes (Heads = H, Tails = T)
The total number of outcomes in the combined event will be equal to the product between the number of outcomes for each event, so we have a total of:
6*2 = 12 events, that have the same probability.
We want to find P(4, H)
This is the probability of rolling a 4 in the die and heads in the penny.
This is one outcome, and we have a total of 12 outcomes (all with the same probability)
Then the probability of each event is equal and should be 1/12 (one over the number of possible outcomes)
We can conclude that the probability P(4,H) = 1/12