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If a = 20 mm, b = 12 mm, and m∠C = 80°, what is the approximate area of ABC?

User Nevus
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1 Answer

5 votes

Answer:

118.18 mm^2

Explanation:

Sides a and b form angle C, so the information given is a side-angle-side (SAS) problem.

Use the formula
A=(1)/(2)absin(C).


A=(1)/(2)(12)(20)sin(80^\circ) \approx 118.18 \rm \,mm^2

User LuxuryWaffles
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