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This was the question it got deleted I just need 1,2,5

This was the question it got deleted I just need 1,2,5-example-1
User Marillion
by
6.0k points

1 Answer

1 vote

Answer:

1. The volume of the cylinder is 263
cm^(3).

2. The volume of the cylinder is 12
m^(3).

3. The volume of the cylinder is 3165.1
cm^(3).

4. The radius of the cylinder is 3.6 cm.

5a. Area of the base is 50.2
cm^(2).

5b. The curved surface area of the pencil holder is 351.7
cm^(2).

5c. The surface are of the pencil holder is 452.2
cm^(2).

Explanation:

1. The given shape is a cylinder, so that;

volume of a cylinder =
\pi
r^(2)h

= 3.14 x
(3.8)^(2) x 5.8

= 262.98128

The volume of the cylinder is 263
cm^(3).

2. This is also a cylinder, but with a given diameter.

radius =
(diameter)/(2)

=
(1.2)/(2) = 0.6 m

volume of a cylinder =
\pi
r^(2)h

= 3.14 x
(0.6)^(2) x 10.6

= 11.98224

The volume of the cylinder is 12
m^(3).

3. volume of a cylinder =
\pi
r^(2)h

= 3.14 x
6^(2) x 28

= 3165.12

The volume of the cylinder is 3165.1
cm^(3).

4. volume of a cylinder =
\pi
r^(2)h

239 = 3.14 x
r^(2) x 6

239 = 18.84
r^(2)


r^(2) =
(239)/(18.84)

= 12.6858

r =
√(12.6858)

= 3.5617

The radius of the cylinder is 3.6 cm.

5. Area of the base =
\pi
r^(2)

radius =
(diameter)/(2)

=
(8)/(2) = 4 cm

Area of the base = 3.14 x
4^(2)

= 50.24

Area of the base is 50.2
cm^(2).

5b. Area of the curved surface of the pencil holder = 2
\pirh

= 2 x 3.14 x 4 x 14

= 351.68

The curved surface area of the pencil holder is 351.7
cm^(2).

5c. Surface area of the pencil holder = 2
\pirh + 2
\pi
r^(2)

= 2
\pir(h + r)

= 2 x 3.14 x 4 (14 + 4)

= 452.16

The surface are of the pencil holder is 452.2
cm^(2).

User Louann
by
5.4k points