Question

Write the log equation as an exponential equation

Answer 1

`\displaystyle {9}^(2x - 1) = 2`

Explanation:

we are given a logarithmic equation

`\displaystyle \log_(9)(2) = 2x - 1`

we want to rewrite it as exponential equation

remember that,

`\displaystyle\log_(a)(b) = c \iff {a}^(c) = b`

here our a is 9,b is 2 and c is 2x-1

altogether

our exponential equation is

`\displaystyle {9}^(2x - 1) = 2`

and we're done!