209k views
4 votes
8.

Find the equation to the line passing through the point of intersection of the lines
3x + 14 =
2y and x + y = 6, and is also perpendicular to the line 5x =
6y + 1.

1 Answer

5 votes

9514 1404 393

Answer:

30x +25y = 148

Explanation:

We can use substitution to find the point of intersection of ...

  • 3x +14 = 2y
  • x + y = 6

Using the second equation, we can write an expression for y:

y = 6 -x

Substituting that into the first equation gives ...

3x +14 = 2(6 -x)

3x +14 = 12 -2x . . . . . eliminate parentheses

5x = -2 . . . . . . . . . . . add 2x-14

x = -0.4 . . . . . . . . . divide by 5

y = 6 -(-0.4) = 6.4

__

Now, we want an equation for a line through the point (-0.4, 6.4) that is perpendicular to 5x = 6y+1

The perpendicular line will have the coefficients swapped with one of them negated. The constant will accommodate the given point.

6x = -5y + c

6(-0.4) +5(6.4) = c = 29.6

The perpendicular line can be written ...

6x = -5y +29.6

In standard form, the equation is ...

30x +25y = 148

8. Find the equation to the line passing through the point of intersection of the-example-1
User KarelPeeters
by
3.5k points