Question

The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argon sample was 14.2 L what what’s the initial volume of the argon sample? Assume ideal behavior

Answer 1

36.09 L

Step-by-step explanation:

The initial volume can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

`V_1 = (P_2V_2)/(P_1) \\`

We have

`V_1 = (7.98 * 14.2)/(3.14) = (113.316)/(3.14) \\ = 36.0878...`

We have the final answer as

36.09 L

Hope this helps you