Answer:
Explanation:
× A = 4y + 2 = 2(4y/2 + 2/2) = 2(2y + 1) ≠ 4(y + 2)
✓ B = 4y + 8 = 4(4y/4 + 8/4) = 4(y + 2) = 4(y + 2)
× C = y + y + y + y + 2 =
y (1 + 1 + 1 + 1) + 2 = 4y + 2 = A ≠ 4(y + 2)
✓ D = 5(y + 2) – (y + 2) = 5(y + 2) – 1(y + 2) =
(5 – 1)(y + 2) = 4(y + 2)
✓ E = y + y + y + y + 2 + 2 + 2 + 2 =
y (1 + 1 + 1 + 1) + (2 + 2 + 2 + 2) =
4y + 8 = B = 4(y + 2)
× F = 5(y + 2) – (y – 2) =
(5y + 10) + (-y + 2) =
(5y – y) + (10 + 2) =
4y + 12 = 4(y + 3) ≠ 4(y + 2)