Answer:
y = 15x + 40
Explanation:
(-3, -5) and (-2, 10)
First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(10 - (-5)) / (-2 - (-3))
Simplify the parentheses.
= (10 + 5) / (-2 + 3)
= 15 / 1
Simplify the fraction.
15/1
= 15
This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.
y = 15x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (-2, 10). Plug in the x and y values into the x and y of the standard equation.
10 = 15(-2) + b
To find b, multiply the slope and the input of x(-2)
10 = -30 + b
Now, add 30 to both sides to isolate b.
40 = b
Plug this into your standard equation.
y = 15x + 40
This is your equation.
Check this by plugging in the other point you have not checked yet (-3, -5).
y = 15x + 40
-5 = 15(-3) + 40
-5 = -45 + 40
-5 = -5
Your equation is correct.
Hope this helps!