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How may moles are in 88.4 grams of Al(OH)3?
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How may moles are in 88.4 grams of Al(OH)3?

How may moles are in 88.4 grams of Al(OH)3?-example-1
User Harry Cho
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1 Answer

6 votes

Answer:

1.133mol Al(OH)3

Step-by-step explanation:

88.4/78.003 = 1.133

User DylanYoung
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