Answer:
Median --> 357.5
Q1 --> 298
Q3 --> 422
IQR > 124
Explanation:
3 daily attendance at the water park: 346, 250, 433, 369, 422,298
Find the median, Q1, Q3,and IQR
Step 1
We rearrange the given data set
250, 298, 346, 369, 422, 433
a) The Median
The formula to find the Median
= 1/2( n + 1)th term
Where n = Number of terms = 6
Median = 1/2(6 + 1)th
= 1/2(7)th term
= 3.5th term
The 3.5th term = The number between the 3rd and 4th term
3rd term = 346
4th term = 369
Hence,Median = 346 + 369/2
= 357.5
2) Q1 = First Quartile
= 1/4(n + 1)the
= 1/4( n + 1)th term
Where n = Number of terms = 6
Median = 1/4(6 + 1)th
= 1/4(7)th term
= 1.75th term
The 1.75th term = 2nd term
= 298
Q1 = 298
3) 3/4( n + 1)th term
Where n = Number of terms = 6
Median = 3/4(6 + 1)th
= 3/4(7)th term = 21/4th term
= 5.25th term
The 5.25th term = 6th term
Q3 = 422
4) Interquartile Range = Q3 - Q1
= 422 - 398
= 124