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19 votes
Solve the follow inequality. ∣3x−4∣≥8

User KOGI
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2 Answers

15 votes
15 votes
X>=4
First step- Add 4 to both sides
Simply-3x>=12
Divide both sides by 3- 3x/3 12/3
X>=4 is final answer
User Anirban
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23 votes
23 votes

Hello.

Let's solve the absolute value inequality.

In order to do that, let's imagine that |3x-4| is positive.

Since the absolute value of |3x-4| is 3x-4, we write 3x-4 and solve:


\mathrm{3x-4\geq 8}

Now, move -4 to the right, using the opposite operation:


\mathrm{3x\geq 8+4}

Add:


\mathrm{3x\geq 12}

Divide both sides by 3:


\mathrm{x\geq 4}

However, this is only 1 solution.

Let's imagine that |3x-4| is a negative number.

So, the inequality looks like so:


\mathrm{-3x+4\geq 8}

Move 4 to the right:


\mathrm{-3x\geq 8-4}


\mathrm{-3x\geq 4}

Divide both sides by -3:


\mathrm{x\leq \displaystyle-(4)/(3) }

Therefore, the solutions are


\mathrm{x\geq 4}\\\mathrm{x\leq \displaystyle-(4)/(3) }


\bigstar Note:

If we divide both sides of an inequality by a negative number, we flip the inequality sign.

I hope this helps you.

Have a nice day.


\boxed{imperturbability}

User DomaNitro
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