Answer:
D. 45.0 g
Step-by-step explanation:
In present reaction, 1 mol of N2 react with 3 moles of H2 to generate 2 moles of NH3
Thus, 2 moles of NH3 ≡ 3 moles of H2
Therefore, 15 moles of NH3 ≡ (3×15)/2 = 22.5 moles of H2.
We know that, 1 mole of H2 ≡ 2 g
Therefore, 22.5 moles of H2 ≡ 2 × 22.5 = 45 g
Thus, 45 g of hydrogen are needed to produce 15.0 mol of ammonia, if the reaction goes to completion