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HELPPPPP!!

Nitrogen and hydrogen react to produce ammonia.

N2(g) + 3H2(g)—>2NH3(g)

How many grams of hydrogen are needed to produce 15.0 mol of ammonia if the reaction goes to completion?

A. 15.0 g
B. 22.5 g
C. 90.0 8
D. 45.0 g

1 Answer

5 votes

Answer:

D. 45.0 g

Step-by-step explanation:

In present reaction, 1 mol of N2 react with 3 moles of H2 to generate 2 moles of NH3

Thus, 2 moles of NH3 ≡ 3 moles of H2

Therefore, 15 moles of NH3 ≡ (3×15)/2 = 22.5 moles of H2.

We know that, 1 mole of H2 ≡ 2 g

Therefore, 22.5 moles of H2 ≡ 2 × 22.5 = 45 g

Thus, 45 g of hydrogen are needed to produce 15.0 mol of ammonia, if the reaction goes to completion

User Matteo Tassinari
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