Answer:
0.482 g of N₂O are produced.
Step-by-step explanation:
The reaction is: 2N₂ + O₂ → 2N₂O
In order to produce 2 moles of N₂O, we need to make react 1 mol of oxygen and 2 moles of nitrogen.
We determine the moles of each reactant:
7.45 g / 28g/mol = 0.266 moles of nitrogen
36.5 mL . 0.15 M = 5.475 mmoles → . 1mol /1000 mmol = 0.00547 moles
Certainly the oxygen is the limiting reactant.
In order to determine the grams produced, we need to know the limiting reactant.
2 moles of N₂ need 1 mol of O₂
Then 0.266 moles of N₂ may react to (0.266 . 1) /2 = 0.133 moles
We only have 0.00547 moles, so there is not enough O₂.
1 mol of O₂ can produce 2 moles of N₂O
Then, the 0.00547 will produce (0.00547 . 2) /1 = 0.01095 moles
We convert to mass: 0.01095 mol . 44 g /mol = 0.482 g
That's the answer.