Question

Find a formula for a geometric sequence that begins 100, 120, 144, ....

Answer 1

`b_(n) =b_(1) r^(n-1) =100*1.2^(n-1)`

Explanation:

first number is
`b_(1) =100`

the cammon ratio is
`r=(120)/(100) =(144)/(120)=1.2`

so
`b_(n) =b_(1) r^(n-1) =100*1.2^(n-1)`