Question

If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence

point in the titration, what is the concentration of the NaOH?

Answer 1

`M_(base)=0.173M`

Step-by-step explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

`n_(acid)=M_(base)V_(base)`

Thus, by solving for the volume of the base as NaOH, we obtain:

`M_(base)=(n_(acid))/(V_(base)) \\\\M_(base)=(0.8675g*(1mol)/(204.22g) )/(0.02456L) \\\\M_(base)=0.173M`

Best regards!