139k views
2 votes
Nolan has some nickels and some dimes he has no more than 19 coins worth no less than $1.30 combined if Nolan has 5 nickels determine all possible values for the number of dimes that he could have

User Tetsuya
by
6.2k points

1 Answer

2 votes

Answer:

10.5 ≤ y ≤ 14

Explanation:

A nickel is worth 5 pennies. Changing over to dollars, it becomes

5/100 = $0.05

A dime is worth dime. Changing over to dollars, it becomes

10/100 = $0.1

Allow x to address the number if nickels.

Allow y to address the quantity of dimes.

He has close to 19 coins. This implies that

x + y ≤ 19

He has no under $1.30 joined. This implies that

0.05x + 0.1y ≥ 1.3

On the off chance that Nolan has 5 nickels, subbing x = 5 into x + y ≤ 19, it becomes

5 + y ≤ 19

y ≤ 19 - 5

y ≤ 14

subbing x = 5 into 0.05x + 0.1y ≥ 1.3, it becomes

0.05 × 5 + 0.1y ≥ 1.3

0.25 + 0.1y ≥ 1.3

0.1y ≥ 1.3 - 0.25

0.1y ≥ 1.05

y ≥ 1.05/0.1

y ≥ 10.5

Along these lines, all potential qualities for the quantity of dimes that he could have would be

10.5 ≤ y ≤ 14

User Fabio Picheli
by
6.1k points