Question

How many grams of KI are needed to prepare 2,000. grams of an aqueous solution

containing 25 parts per million (ppm) of solute?

Answer 1

`m_(solute)=0.05g`

Step-by-step explanation:

Hello there!

In this case, according to the equation for the calculation of the parts per million:

`ppm=(m_(solute))/(m_(solution)) *1x10^6`

It is possible to solve for the mass of KI (solute) as shown below:

`m_(solute)=(ppm*m_(solution))/(1x10^6)`

Thus, we plug in to obtain:

`m_(solute)=(25*2,000g)/(1x10^6) \\\\m_(solute)=0.05g`

Best regards!