16ef³÷8e²f= 24m²n³ _____= 2mn 2k³+k _____= 4k

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asked Apr 28, 2022 50.2k views

2 votes

16ef³÷8e²f=

24m²n³
_____=
2mn

2k³+k
_____=
4k

Mathematics
high-school

Stukselbax asked

by Stukselbax

8.1k points

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1 Answer

4 votes

Answer:

Answer is below

Explanation:

16ef³÷8e²f=
(2f^(2))/(e)

(24m^(2) n^(3) )/(2mn) = 12m n^(2)

(2k^(3) +k)/(4k) =(1)/(2) k^(2) +(1)/(4)

BlueFox answered May 2, 2022

by BlueFox

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