Question

Quadratic formula to find the zeros
b^2-4b+4=0

Answer 1

Explanation:

Remark

I don't think you need the quadratic formula for this equation. It just factors into (b - 2)(b - 2), but I'll do it because you requested it.

Formula

`\text{x = }\frac{ -b \pm \sqrt{b^(2) - 4ac } }{2a}`

Givens

a = 1

b = - 4

c = 4

Solution

x = - - 4 +/- sqrt((-4^2) - 4*1*4)

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2*1

x = 4 +/- sqrt (16 - 16)

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2

x = 4/2

x = 2

There are 2 roots but both of them are the same. Some teachers say there is only 1 root. I'm in that group.