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A 108.9 g sample of water absorbs 114.6 calories of heat. The specific heat capacity of water is 1 cal/(g·°C). By how much did the temperature of this sample change, in degrees Celsius?

User Liabru
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1 Answer

4 votes

Answer:

The temperature of this sample changes by 1.052 degrees Celsius

Step-by-step explanation:

As we know


Q = mc\Delta T

Where m is the mass of the substance

c is the specific heat of the substance

and
\Delta T is the change in temperature

Substituting the given values in above equation, we get -


114.6 = 108.9 * 1 * \Delta T\\\Delta T = 1.052degree Celsius

The temperature of this sample changes by 1.052 degrees Celsius

User Phenomnomnominal
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