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3 votes
A 2.5 V battery is connected to a small light

bulb with a resistance of 4.8 Ω .
What is the current in the bulb?
Answer in units of A.

User AJak
by
4.8k points

1 Answer

6 votes

Answer: I=0.52 A

Step-by-step explanation:

Given

Voltage is
2.5\ V

Resistance
R=4.8\ \Omega

Current is given by


I=(V)/(R)


\Rightarrow I=(2.5)/(4.8)=0.52\ A

User Nitin Purohit
by
4.5k points