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What volume, in liters, does the following quantity of gas at STP occupy?

7.8*10^15

thank you

User Rawler
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1 Answer

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Answer:

2.9x10⁻⁷L is the volume this amount of gas occupy

Step-by-step explanation:

Assuming there are 7.8x10¹⁵ atoms

Based on the general gas law:

PV = nRT

Where P is pressure = 1atm

V is volume = Our incognite

n are moles of the gas:

7.8x10¹⁵ atoms * (1mol / 6.022x10²³ atoms) = 1.30x10⁻⁸ moles of gas

R is gas constant = 0.082atmL/molK

And T is absolute temperature = 273.15K at STP

Solving for Volume:

V = nRT/P

V = 1.30x10⁻⁸ moles*0.082atmL/molK*273.15K / 1atm

V = 2.9x10⁻⁷L is the volume this amount of gas occupy

User Vinayak Kolagi
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