Answer:
Explanation:
2 Ms. Salgato doesn’t want to spend more than $375 that in symbols can be expressed as
.
$100 is a constant so it doesn’t multiplies the x. The hour are instead a variable so $40 multiplies the x
so the final answer is
C
![100+40x\leq 375](https://img.qammunity.org/2022/formulas/mathematics/middle-school/zlfgezqa8ygsewh78t1s2f5twa5ac3sbgg.png)
9 no less than $455 can expressed as
![\geq 455](https://img.qammunity.org/2022/formulas/mathematics/middle-school/68w9rj8vzixw7282vjub107lol79u19e2x.png)
if we solve the inequality
![245+d\geq 455](https://img.qammunity.org/2022/formulas/mathematics/middle-school/b7ydwcmvqh9tzzdjozdnt5yijvwq4y96ou.png)
we have
![d \geq 210](https://img.qammunity.org/2022/formulas/mathematics/middle-school/kpaal52ohaqfqzwzgyzs3lqdj36mk06wc3.png)
so the final answer is A
13
$130 is a constant, while $3 mulplied a variable. No more means
![\leq 190](https://img.qammunity.org/2022/formulas/mathematics/middle-school/b8hposna141xzlzru3fsrd0lwvsf2phirx.png)
we can now write and solve an inequality:
![130+3x\leq 190 \\ 3x\leq 60 \\ x\leq 20](https://img.qammunity.org/2022/formulas/mathematics/middle-school/1g9bkqso18kr87bqpb6qm4b40mrbrqbtak.png)
so the answer is C : 20
14
$9 multiplies a variable, a minimum can be expressed as
![\geq](https://img.qammunity.org/2022/formulas/computers-and-technology/college/lifms4ly420epeq3mh7nzye306x4se5w.png)
so the final answer is
B :
![9h\geq 81](https://img.qammunity.org/2022/formulas/mathematics/middle-school/1zm37ab9b8q631qvq2jxkg8ucyzpm23991.png)