57.4k views
4 votes
A jar contains 4 green marbles and 6 yellow marbles. Two marbles are drawn, with replacement, from the jar. What is the probability that both marbles are green?

User Thierryb
by
6.3k points

2 Answers

4 votes

Final answer:

The probability of drawing two green marbles with replacement from a jar containing 4 green marbles and 6 yellow marbles is 0.16.

Step-by-step explanation:

The question involves calculating the probability of drawing two green marbles from a jar that contains a mix of green and yellow marbles, with the draw being with replacement. This means after drawing a marble, it is put back into the jar before drawing the next one.

To find the probability of two independent events both happening, we multiply the individual probabilities. Since there are 4 green marbles out of a total of 10 (4 green and 6 yellow), the probability of drawing a green marble on the first draw is 4/10 or 0.4. With replacement, the second draw has the same probability of 4/10 as the first draw.

Therefore, the probability of drawing a green marble twice with replacement is calculated as:

P(green and green) = P(green on first draw) × P(green on second draw) = 0.4 × 0.4 = 0.16.

User Swagg
by
6.9k points
4 votes

Answer:

If there are a total of 10 marbles in jar, then It´s a 4/10 chance you get two marbles that are green

Step-by-step explanation:

User AndrewMinCH
by
6.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.