Question

A ballon is filled with 1.22 L of gas at 286 K is heated until the volume is 2.86 L while the pressure remains constant. What is the temperature of the gas in kelvin?

Answer 1

670.45 K

Step-by-step explanation:

Given that,

Initial volume, V₁ = 1.22 L

Initial temperature, T₁ = 286 K

Final volume, V₂ = 2.86 L

We need to find the new temperature of the gas. The relation between the volume and the temperature is given by :

`(V_1)/(T_1)=(V_2)/(T_2)\\\\T_2=(V_2T_1)/(V_1)\\\\T_2=(2.86* 286)/(1.22)\\\\T_2=670.45\ K`

So, the new temperature of the gas is equal to 670.45 K.