Answer:
6.12 L
Step-by-step explanation:
Given that,
Initial volume, V₁ = 5 L
Initial temperature, T₁ = 7.0°C = 343 K
Final temperature, T₂ = 147°C = 420 K
We need to find its new volume. The relation between volume and temperature is given by :
![(V_1)/(T_1)=(V_2)/(T_2)\\\\V_2=(V_1T_2)/(T_1)\\\\V_2=(5* 420)/(343)\\\\V_2=6.12\ L](https://img.qammunity.org/2022/formulas/chemistry/college/14asgbglhjse2zx5sx6a7opaxkxheo4mnh.png)
So, the new volume is 6.12 L.