Answer:
I. L = 17 cm.
II. W = 11 cm.
Explanation:
Let the length of the rectangle be L.
Let the width of the rectangle be W.
Given the following data;
Perimeter of rectangle = 56cm
Translating the word problem into an algebraic expression, we have;
L = W + 6 .....equation 1
The perimeter of a rectangle is given by the formula;
P = 2(L + W)
56 = 2(L + W) ......equation 2
Substituting eqn 1 into eqn 2, we have;
56 = 2(W + 6 + W)
56 = 2(6 + 2W)
Opening the bracket, we have;
56 = 12 + 4W
4W = 56 - 12
4W = 44
W = 44/4
W = 11 cm
Next, we would find the length of the rectangle;
From eqn 1;
L = W + 6
L = 11 + 6
L = 17 cm