Question

Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Show all your work.

Answer 1

Answer: The freezing point depression is
`1.86^0C`

Step-by-step explanation:

Depression in freezing point is given by:

`\Delta T_f=K_f* m`

`\Delta T_f` = Depression in freezing point

`K_f` = freezing point constant =
`1.86^0C/m`

m= molality =
`\frac{\text {moles of solute}}{\text {mass of solvent in kg}}=(2mol)/(2kg)=1m`

`\Delta T_f=1.86mol/kg^0C* 1m`

`\Delta T_f=1.86^0C`

Thus freezing point depression is
`1.86^0C`