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29 votes
Factoring polynomials

Factoring polynomials-example-1
User Abhay Buch
by
2.8k points

2 Answers

24 votes
24 votes

Answer:

Final result :

(j - 1) • (7j - 3)

Explanation:

Step by Step Solution

STEP1:

Equation at the end of step 1

(7j2 - 10j) + 3

STEP2:

Trying to factor by splitting the middle term

2.1 Factoring 7j2-10j+3

The first term is, 7j2 its coefficient is 7 .

The middle term is, -10j its coefficient is -10 .

The last term, "the constant", is +3

Step-1 : Multiply the coefficient of the first term by the constant 7 • 3 = 21

Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 .

-21 + -1 = -22

-7 + -3 = -10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3

7j2 - 7j - 3j - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

7j • (j-1)

Add up the last 2 terms, pulling out common factors :

3 • (j-1)

Step-5 : Add up the four terms of step 4 :

(7j-3) • (j-1)

Which is the desired factorization

Final result :

(j - 1) • (7j - 3)

User Akshay Tilekar
by
2.8k points
16 votes
16 votes

Answer: (j-1)(7j-3)

Explanation:

Factoring polynomials-example-1
User Kennydust
by
3.1k points