Question

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠O=84°, and OP = 2. 9 feet. Find the length of PQ to the nearest tenth of a foot

Answer 1

OP= 27. 6

Step-by-step explanatexplanation:

In triangle OPQ: Ô+P+Q =180

therefore <P= 6°

OQ= OP sinsinà

OP= OQ/ sinà

OP= 2.9/ sin6°

OP= 27.7 ft

using pythagoras

OP^2 = PQ^2 + OQ^2

PQ= sqrt( 27.74^2 - 2.9^2)

PQ= 27.27.6