Given P(A) = 0.44, P(B) 0.6 and P(An B) = 0.394, find the value of P(AUB), rounding to the nearest thousandth, if necessary.

Question

asked Feb 17, 2022 225k views

1 Answer

Lorrie · Answer 1 · 2022-02-21T16:10:22+0000

Given:

$P(A)=0.44,P(B)=0.6,P(A\cap B)=0.394$ .

To find:

The value of
$P(A\cup B)$ , rounding to the nearest thousandth.

Solution:

We know that,

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

On substituting
$P(A)=0.44,P(B)=0.6,P(A\cap B)=0.394$ , we get

$P(A\cup B)=0.44+0.6-0.394$

$P(A\cup B)=0.646$

Therefore, the value of
$P(A\cup B)$ is 0.646.