Question

A sample of unknown gas has a temperature of 378k. When the temperature is increased to 546k,the volume also increases to 1047 ml. What was the original volume ?

Answer 1

Given :

A sample of unknown gas has a temperature of 378 K.

`T_i = 378 \ K , \ T_f = 546 \ K`

When the temperature is increased to 546 K, the volume also increases to 1047 ml.

`V_f - V_i = 1047 \ ml`

Solution :

We know, temperature is directly proportional to volume.

`(T_i)/(T_f)=(V_i)/(V_f)\\\\(T_i)/(T_f) = (V_i)/(1047 + V_i)\\\\(V_i)/(1047+V_i)=(378)/(546)\\\\546V_i = 378V_i + 378* 1047\\\\168V_i = 3,95,766\\\\V_i = 2,355.75\ ml`

Therefore, the original volume is 2.355.75 ml.