Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, what must be true about area II and area III.

Question

asked Apr 26, 2022 186k views

1 Answer

Conan · Answer 1 · 2022-05-02T01:19:45+0000

Answer:

See Explanation

Explanation:

Given

Total = x^2 + 14x + 24

$Area\ I = x^2$

$Area\ IV = 24$

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

Total = x^2 + 14x + 24

And there are 4 areas, then;

$Total = Area\ I + Area\ II + Area\ III + Area\ IV$

Rewrite as:

$Total = Area\ I + Area\ IV+ Area\ II + Area\ III$

This gives:

$x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III$

Collect like terms

$x^2 -x^2 + 14x + 24 -24= Area\ II + Area\ III$

$14x = Area\ II + Area\ III$

Rewrite as:

$Area\ II + Area\ III = 14x$

So, the sum of areas III and IV must be 14x