3a-2/3+2a+3/2=a+7/6.find a

Question 1

Question 2

I think your question seems to be ;

${\:\implies \quad \sf 3a-\frac23 +2a+\frac32 =a+\frac76}$

So I will be solving for that ;

${\:\implies \quad \sf 3a+2a+\left(\frac32 -\frac23\right)=a+\frac76}$

${\:\implies \quad \sf 5a+\left((9-4)/(6)\right)=a+\frac76}$

${\:\implies \quad \sf 5a+\frac56 =a+\frac76}$

${\:\implies \quad \sf 5a-a=\frac76 -\frac56}$

${\:\implies \quad \sf 4a=(7-5)/(6)}$

${\:\implies \quad \sf 4a=\frac26}$

${\:\implies \quad \sf 4a=\frac13}$

${\:\implies \quad \sf a=(1)/(3\cdot 4)}$

${\:\implies \quad \bf \therefore \quad \underline{\underline{a=(1)/(12)}}}$

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