Question

A waiter walks a distance of 5m holding a tray of food that weighs 10N. How much work has the waiter done on the tray?

Answer 1

Force(10N)xDistance(5m)=50j(work done)

Answer 2

0 joule of workdone

Step-by-step explanation:

`w = f * d * \cot( \beta )`

force and the displacement are perpendicular to each other so cos(90⁰) =0