Answer:
![\boxed {\boxed {\sf v \approx 1.46 \ m/s}}](https://img.qammunity.org/2022/formulas/physics/high-school/1iafvezzv7i69pie9jnp6rh32lc9urcyu4.png)
Step-by-step explanation:
Momentum is the product of mass and velocity.
![p=mv](https://img.qammunity.org/2022/formulas/physics/high-school/isv7fjvtv7ozvekhxh9cgnhfetg7ebex5z.png)
We know the mass is 65 kilograms and the momentum is 90 kilograms meters per second.
![m= 65 \ kg \\p= 95 \ kg \ m/s](https://img.qammunity.org/2022/formulas/physics/high-school/yn1o6a2yflz1qfo20dghw56dye56xt9clq.png)
Substitute the values into the formula.
![95 \ kg \ m/s= 65 \ kg *v](https://img.qammunity.org/2022/formulas/physics/high-school/3519cbc9qztk3z15lh2hzqzthhaufth6h9.png)
Since we are solving for velocity, we must isolate the variable (v). It is being multiplied by 65 kg. The inverse of multiplication is division, so we divide.
![\frac {95 \ kg \ m/s}{65 \ kg }= \frac {65 \ kg *v}{65 \ kg}](https://img.qammunity.org/2022/formulas/physics/high-school/j80evp22gbv35s87n82qzdv7994stl19cz.png)
![\frac {95 \ kg \ m/s}{65 \ kg }=v](https://img.qammunity.org/2022/formulas/physics/high-school/vgqf7anrzomuuy43w7evx0ezft6pc951sa.png)
The kilograms cancel when divided.
![1.46153846 \ m/s=v](https://img.qammunity.org/2022/formulas/physics/high-school/j9n868b93lq3xoogioj537jnf5u5pf4dsd.png)
Let's round to the nearest hundredth. The 1 (in the thousandth place) tells us to leave the 6.
![1.46 \ m/s \approx v](https://img.qammunity.org/2022/formulas/physics/high-school/8k97s9afyjs0yihiwg40m41dqk44fosl1j.png)
The velocity is approximately 1.46 meters per second.