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You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 8 feet more than the width.
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You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 8 feet more than the width. Find the width of the rectangle, in feet.

User Inputforcolor
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Answer:

44=2[(w+8)+w]

44=4w+16

28=4w

w=28/4

w=7feet

User Mcmlxxxvi
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