Question

B r u h. Just help for points. No answer no points

Answer 1

`\left(-34, (33)/(2)\right)`

Explanation:

Create a linear equation for line AB and line CD

Find slope using slope formula
`m=(y_2-y_1)/(x_2-x_1)`

then use point-slope form of linear equation
`y-y_1=m(x-x_1)`

(where m is the slope and
`(x_1,y_1)` and
`(x_2,y_2)` are two points on the line)

Line AB

`m=(-16+1)/(-8+20)=-\frac54`

`\implies y+1=-\frac54(x+20)\\\\\implies y=-\frac54x-26`

Line CD

`m=(0+11)/(-19+9)=-(11)/(10)`

`\implies y+11=-(11)/(10)(x+9)\\\\\implies y=-(11)/(10)x-(209)/(10)`

To find the point of intersection, equate the equations and solve for x::

AB = CD

`\implies -\frac54x-26=-(11)/(10)x-(209)/(10)`

`\implies -(3)/(20)x=(51)/(10)`

`\implies x=-34`

Substitute found value of x into one of the equations and solve for y:

`y=-\frac54(-34)-26=(33)/(2)`

Therefore, point of intersection is
`\left(-34, (33)/(2)\right)`