Question

What is an
equation of the line that passes through the points (-6, -6) and (3,6)?

Answer 1

`y=\frac43x+2`

Explanation:

Find slope using slope formula
`m=(y_2-y_1)/(x_2-x_1)`

then use point-slope form of linear equation
`y-y_1=m(x-x_1)`

(where m is the slope and
`(x_1,y_1)` and
`(x_2,y_2)` are two points on the line)

Let
`(x_1,y_1)` = (-6, -6)

Let
`(x_2,y_2)` = 3, 6)

`\implies m=(y_2-y_1)/(x_2-x_1)=(6+6)/(3+6)=\frac43`

`\implies y+6=\frac43(x+6)`

`\implies y=\frac43x+2`