Question

PQRS is a parallelogram. Point V is on ray SR such that SR ~=RV, then prove that line PV bisects seg QR at point T. i.e., seg QT= seg TR)​

Answer 1

We have,

According to given figure.

PQ=PR(given that)

QS=SR(Bydefinationofmidpoint)

PS=PS(Commonline)

Then,

ΔSPQ≅ΔSPR (BY congruency S.S.S.)

Hence, PS bisects ∠PQR by definition of angle bisector.