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The owner of a pizza restaurant in France knows that the time customers spend in the restaurant on Saturday evening has mean 90 minutes and standard deviation 15 minutes. He has read that pleasant odors can influence customers, so he spreads a lavender odor throughout the restaurant. Presented are the times, in minutes, for customers on the next Saturday evening.

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Answer:

hello your question is incomplete attached below is the missing part

Question : What is the value of the test statistic

answer : = 5.73

Explanation:

Mean value = 90 minutes

std = 15 minutes

Calculate the test statistic

mean value of given data = ∑ x / n = 105.7

since the value of standard deviation is given we will assume a normal distribution

Hence we will apply z test statistics

z = mean value of given data - Mean value / 15 √30

= ( 105.7 - 90 ) / 15 √30

= 5.73

The owner of a pizza restaurant in France knows that the time customers spend in the-example-1
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