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A man's speed is 50 m/s and his mass is 120 kg. What is his kinetic energy just before running back up? |

kg*m/s

User Logicnp
by
7.3k points

1 Answer

2 votes

Answer:

150,000 Joules

Step-by-step explanation:

KE= 1/2 *mv^2

1/2 * 120 *50^2

60*2500

150,000 Joules

Hope this helps :)

User Rbrc
by
7.1k points