Question

How can i solve this
(x+2)(2x+3)
step by step please

Answer 1

2x^2+7x+6

Explanation:

Expand the polynomial (An algebraic expression) using the FOIL (First, Outer, Inner, Last) method.

2x^2+7x+6

(x+2)(2x+3)

First, multiply the variables (x).

(x)(2x) = 2x^2

• NOTE: the '^' before a number is used to signify an exponent.

Then, multiply the whole numbers (2, 3).

(2)(3) = 6

Now, you're not done. You need to multiply the variables and the whole numbers (that weren't already multiplied together)

(x)(3) = 3x

(2)(2x) = 4x

• NOTE: make sure you're multiplying one expression to the other, not multiplying the same expression together.

Finally, add them all together, and simplify.

2x^2 + 6 +3x + 4x

=

2x^2+7x+6

Answer 2

2x² + 7x + 6

Explanation:

To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).

You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.

(x+2)(2x+3)

2x²+ 3x + 4x + 6

2x² +7x + 6