Question

Please help me with this question!!

Answer 1

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`
`\text{Moles of} Cl_2=(500.00g)/(71g/mol)=7.04moles`

`2Na+Cl_2\rightarrow 2NaCl`

According to stoichiometry :

1 mole of
`Cl_2` produce = 2 moles of
`NaCl`

Thus 7.04 moles of
`Cl_2` will produce=
`(2)/(1)* 7.04=14.08moles` of
`NaCl`

Mass of
`NaCl=moles* {\text {Molar mass}}=14.08moles* 58.5g/mol=824.26g`

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.