Question

d. 2 5. How many moles of HCl are needed to produce 25 moles of KCl in the presence of excess potassium permanganate? a. 16 b. 32 c. 5 d. 200​

Answer 1

d. 200.

Step-by-step explanation:

The reaction is:

2KMnO4 + 16HCl ----> 2KCl + 2MnCl2 + 8H2O + 5Cl2

So 2 moles of KCL are produced form 16 moles of HCL

So 25 moles KCL are made from 25 * (16/2) HCl.

= 25 * 8

= 200 moles. HCl.