Question

A factory produces steel components for use by a number of different

companies. The density of the steel used by the factory is 8000 kg/mº,
A partoutor steel oube produced by the factory has a side length of 5 em,
5 cm
5 cm
5cm
Calculate the mass of one of these cubes. Write your answer in
kilograms

Answer 1

1 kg

Step-by-step explanation:

Since density ρ = m/v where m = mass of steel cube and v = volume of steel cube = L³ where L= side length of steel cube = 5 cm = 0.05 m

Now, m = ρv = ρL³

Since ρ = 8000 kg/m³,

m = ρL³

= 8000 kg/m³ × (0.05 m)³

= 8000 kg/m³ × 0.000125 m³

= 1 kg